100-x^2=x^2+14/3x

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Solution for 100-x^2=x^2+14/3x equation: 


x in (-oo:+oo)

100-x^2 = x^2+(14/3)*x // - x^2+(14/3)*x

100-x^2-x^2-((14/3)*x) = 0

(-14/3)*x-x^2-x^2+100 = 0

100-2*x^2-14/3*x = 0

DELTA = (-14/3)^2-(-2*4*100)

DELTA = 7396/9

DELTA > 0

x = ((7396/9)^(1/2)+14/3)/(-2*2) or x = (14/3-(7396/9)^(1/2))/(-2*2)

x = -25/3 or x = 6

x in { -25/3, 6 }

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